Created
March 30, 2020 15:16
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Grafici e raggruppamento dati: soluzioni esercizi
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| # ESERCIZIO 1 | |
| # 1a | |
| tips.loc[0, "size"] | |
| # 1b | |
| tips.loc[tips["total_bill"].idxmax()] | |
| # 1c | |
| tips["tip"].mean() | |
| # 1d | |
| (tips["total_bill"] / tips["size"]).max() | |
| # ESERCIZIO 2 | |
| # 2a | |
| (tips["total_bill"] / tips["size"]).describe() | |
| # 2b | |
| pd.cut(tips["tip"] / tips["total_bill"], 3).value_counts() | |
| # ESERCIZIO 3 | |
| # 3a | |
| pd.cut(tips["total_bill"], 3).value_counts().plot.pie(); | |
| # 3b | |
| tips.loc[tips["time"] == "Dinner", "day"].value_counts().plot.pie(); | |
| # 3c | |
| (tips["tip"] / tips["total_bill"]).plot.hist(); | |
| # 3d | |
| (tips["tip"] / tips["total_bill"]).plot.box(); | |
| # 3e | |
| tips.plot.scatter("tip", "size"); | |
| # 3f | |
| for n, day in enumerate(["Thur", "Fri", "Sat", "Sun"], start=1): | |
| tips.loc[tips["day"] == day, "smoker"].value_counts().plot.bar(ax=plt.subplot(2, 2, n), title=day) | |
| # ESERCIZIO 4 | |
| # 4a | |
| tips.groupby("smoker")["size"].mean() | |
| # 4b | |
| tips.groupby("day")["tip"].agg(["sum", "mean"]) | |
| # 4c | |
| tips.loc[tips["day"] == "Fri"].groupby("time")["tip"].mean() | |
| # 4d | |
| tips.groupby(tips["total_bill"] >= 20)["tip"].mean() | |
| # ESERCIZIO 5 | |
| # 5a | |
| tips.groupby(["day", "time"]).size().unstack(fill_value=0) | |
| # 5b | |
| tips.pivot_table(values="tip", | |
| index="day", | |
| columns="time", | |
| aggfunc="sum", | |
| fill_value=0) | |
| # 5c | |
| tips.pivot_table(values=["total_bill", "tip"], | |
| index=pd.cut(tips["total_bill"], 3), | |
| columns="time") |
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