Created
February 7, 2022 18:03
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DKatalis Solution for Q2
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| def t1Resource(x): | |
| existCheckt1 = resource.count(x) | |
| if existCheckt1 > 0: | |
| T1.append(x) | |
| resource.remove(x) | |
| else: | |
| res = min(resource) | |
| T1.append(res) | |
| resource.remove(res) | |
| def t2Resource(y): | |
| existCheckt1 = resource.count(y) | |
| if existCheckt1 > 0: | |
| T2.append(y) | |
| resource.remove(y) | |
| else: | |
| res = min(resource) | |
| T2.append(res) | |
| resource.remove(res) | |
| if __name__ == "__main__": | |
| resource = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] | |
| # or if you want custom length of resource | |
| """ | |
| nResource = int(input()) | |
| for i in range(nResource): | |
| resource = [int(x) for x in input().split()] | |
| """ | |
| T1 = [] | |
| T2 = [] | |
| flag = True | |
| while flag: | |
| for i in range(len(resource)): | |
| if len(resource) != 0: | |
| t1 = int(input("Add resource for T1: ")) | |
| t1Resource(t1) | |
| t2 = int(input("Add resource for T2: ")) | |
| t2Resource(t2) | |
| else: | |
| flag = False | |
| break | |
| break | |
| print("T1 : {0}".format(T1)) | |
| print("T2 : {0}".format(T2)) |
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