Created
January 20, 2026 16:17
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Kattis driversdilemma
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| use std::io::{Read, stdin}; | |
| fn main() { | |
| let mut s = String::new(); | |
| stdin().read_to_string(&mut s).unwrap(); | |
| let mut lines = s.lines(); | |
| let mut pp = lines | |
| .next() | |
| .unwrap() | |
| .split_whitespace() | |
| .map(|s| s.parse::<f64>().unwrap()); | |
| let cap = pp.next().unwrap(); | |
| let leak = pp.next().unwrap(); | |
| let dist = pp.next().unwrap(); | |
| let fuel = cap / 2.0; | |
| let speeds = lines | |
| .map(|l| { | |
| l.split_once(' ') | |
| .map(|(l, r)| (l.parse::<f64>().unwrap(), r.parse::<f64>().unwrap())) | |
| .unwrap() | |
| }) | |
| .collect::<Vec<_>>(); | |
| // Just find biggest speed we can go to get to distance. | |
| for (speed, mpg) in speeds.iter().rev() { | |
| let time = dist / speed; | |
| let consumed = dist / mpg; | |
| let leaked = leak * time; | |
| let needed = consumed + leaked; | |
| if needed <= fuel { | |
| println!("YES {}", *speed as isize); | |
| return; | |
| } | |
| } | |
| println!("NO"); | |
| } |
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