http://www.freecodecamp.com/duggiemitchell 's solution for Bonfire: Seek and Destroy

bonfire-seek-and-destroy.js

// Bonfire: Seek and Destroy
// Author: @duggiemitchell
// Challenge: http://www.freecodecamp.com/challenges/bonfire-seek-and-destroy
// Learn to Code at Free Code Camp (www.freecodecamp.com)

function destroyer(arr) {
 
  var argCombo = arr.slice.call(arguments);
  
  console.log(argCombo.splice(0,1));

  return arr.filter(function(chr) {
     return argCombo.indexOf(chr) === -1;
    
     }
     
     
  );
}
  


destroyer([1, 2, 3, 1, 2, 3], 2, 3);

Fist, we must turn the arguments into an array using arr.slice.call(arguments); and assign to the variable argCombo

The splice method modifies the argCombo array and returns the deleted elements as a new array ``console.log(argCombo.splice(0,1)); //output: [1,1]

Now, using the filter() function on arr to remove elements we dont want and return ones we wish to keep. In this case, chr is assigned to elements in array will return chr that are === -1 since filter() returns -1 (or false) for chr that are not present in the array