linear_search_updateed.py

#!/bin/python3
import os 
import time as t
#this import is not being used
from time import sleep 
os.system("clear")
def lsearch(array:list, search_element:any)->None:
  #I commented the lines with sleep to be fair on the timing below
	#t.sleep(0.1)
	print("\nMethod:linear search")
	#t.sleep(0.1)
	print("You entered:  ",list(array),type(array))
	#t.sleep(0.1)
	print("Search Element is:  ",search_element,type(search_element))
	#t.sleep(0.1)
	print("Searching started ")
	#t.sleep(0.1)
	print("Checking..")
  # variable i is not required as it is handled by the for loop
	i = 0
	for i in range(len(array)):
		if array[i] == search_element:
			#t.sleep(0.1)
			print("Element is Found at",  i,"th index and",  i+1,  "th position")
			#t.sleep(0.1)
			print("Completed chacking. ")
			#t.sleep(0.1)
			print("Searching ended")
			break
		# else statement is not required here 'cause above you a have a break
		else:
			pass
      # you are recalculating the size of the array why not save that value,
      # in a variable before starting the loop
			if i==len(array)-1:
				#t.sleep(0.1)
				print("Element not found ")
				#t.sleep(0.1)
				print("Completed chacking.")
				#t.sleep(0.1)
				print("Searching ended")
		# why will you need to increment i variable value?
    # its value is handled  by the for loop
		i = i+1


def lsearch_v2(array:list, search_element:any)->None:
  size = len(array)
  found = False
  for i in range(size):
    if array[i] == search_element:
      found = True
      break

  if found:
    print("Element is Found at"+ str(i) +"th index and"+  str(i+1)+  "th position")
  else:
    print("Element not found ")


t1 = t.perf_counter()
#lsearch doesn't return a result so no need to variable holding that result
l1 = lsearch([1,2,3,4,5,6,7],'tejas')
l2 = lsearch(['tejas','kunal','vignesh','datta','saif'],5)
l3 = lsearch(['appale',1,2,3,'mango'],1)
print("Time for first approach: %f" % (t.perf_counter() - t1))

t1 = t.perf_counter()
lsearch_v2([1,2,3,4,5,6,7],'tejas')
lsearch_v2(['tejas','kunal','vignesh','datta','saif'],5)
lsearch_v2(['appale',1,2,3,'mango'],1)
print("Time for second approach: %f" % (t.perf_counter() - t1))