Create a Surface Plot from a Matrix #numpy #matplotlib #python

figure.png

surface_plot.py

import numpy as np
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D

def surface_plot (matrix, **kwargs):
    # acquire the cartesian coordinate matrices from the matrix
    # x is cols, y is rows
    (x, y) = np.meshgrid(np.arange(matrix.shape[0]), np.arange(matrix.shape[1]))
    fig = plt.figure()
    ax = fig.add_subplot(111, projection='3d')
    surf = ax.plot_surface(x, y, matrix, **kwargs)
    return (fig, ax, surf)

# m.shape must be (10,10)
m = np.fromfunction(lambda x, y: np.sin(np.sqrt(x**2 + y**2)), (10, 10))

(fig, ax, surf) = surface_plot(m, cmap=plt.cm.coolwarm)

fig.colorbar(surf)

ax.set_xlabel('X (cols)')
ax.set_ylabel('Y (rows)')
ax.set_zlabel('Z (values)')

plt.show()

how to defend result a (matrix line * matrix clone) in python as function. help me

Change:

(x, y) = np.meshgrid(np.arange(matrix.shape[0]), np.arange(matrix.shape[1]))

to:

(x, y) = np.meshgrid(np.arange(matrix.shape[1]), np.arange(matrix.shape[0]))

in order to remove the restriction that m.shape must be square.